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  • Question #33eb8 - Socratic
    First, subtract #color (red) ($145)# from each side of the equation to isolate the #w# term while keeping the equation balanced:
  • Question #5b826 - Socratic
    What we're really doing here is that we're given an initial state with # ["BrCl"]_i = "0 050 M"#, and we're given #K_ (eq)#, which is defined for a final state we define as equilibrium, when the rate of the forward reaction is equal to that of the reverse reaction
  • Question #933a2 - Socratic
    Solve: 1 sin x = 0 5623 2 cos x = 0 8963 3 tan x = -2 89 1 Calculator gives --> sin x = 0 5623 --> x = 34 22 and x = 180 - 34 22 = 145 78 deg Extended answers: x = 34 22 + k360 deg x = 145 78 + k360 deg 2 cos x = 0 8963 --> x = +- 26 32 deg Extended answers: x = +- 26 32 + k360 deg 3 tan x = -2 89 --> x = -70 93 and x = -70 93 + 180 = 109 09 deg Extended answers: x = 109 09 + k180 deg
  • Question #43ae5 - Socratic
    You can then visit your scratchpad by clicking on the drop-down menu located right next to your profile name and profile image (top right of the page) and selecting My Scratchpads
  • Question #b56ad - Socratic
    Explanation: Velocity of man just prior to landing on the pad #=4 4ms^-1# Momentum of man just prior to landing on the pad #p=mv# #=50xx4 4=220kgms^-1#
  • Question #3bc9f - Socratic
    The smallest integer, we now know the smallest integer is -3 Let n be the smallest of the four integers That means the other integers are n+1, n+2, n+3 The problem says that we should sum up these four numbers: n+n+1+n+2+n+3 = 4n+6 This sum is thrice the second integer The second integer is n+1 So we know that 4n+6=3(n+1) Now we solve this equation: 4n+6=3n+3 n=-3 n=-3 Since n is the
  • Question #83d7a - Socratic
    Question 4: Let's call your current age x Your dad is 35-7=28 years older than you are, so his current age is x+28 So we get: Dad=3*you, or: x+28=3*x->x=14->3*x=42 Answer : You are 14 now, and your dad is 42 Check: x+28=14+28=42
  • Question #4f991 - Socratic
    42,000 “Rounding” is usually done at a value of ‘5’ because our accuracy can at best be only + - (1 2) of the last digit So, if the value to the right of a number is 4 or less we make no change to the number If the value to the right of a number is 5 or more we increase the value of the number by one (1) In this case the number to the right of the “thousands” is a ‘5’ in
  • Question #67a25 - Socratic
    (2 5*10^-11"mol") L When Pb(IO)_3 dissociates in water it forms Pb^+ + IO_3^- If x = molar solubility then "Therefore Ksp" = [Pb^+][IO_3^-]^2 "Or Ksp"(2 5*10^-13) = [x][2x]^2 As it is in a NaIO_3 of 0 100M and you want the molar solubility of Pb(IO)_3 in NaIO3 and not in water 2 5*10^-13 = [x][x + 0 1M]^2 But x is so so so so small that we can ignore it Therefore x + 0 1 = 0 1 Solve for x





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