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  • Question #26469 - Socratic
    Electric Meters usually measure in KWH units KWH is acronym for Kilo Watt Hour It's basically units of Work Energy You can do the math for the Kilo Watt Hour It's simple KWH = 1000* 60*60 Watt-Sec rArr KWH = 3 6*10^6 Watt-Sec We know that, Power = (Work) (Time) Units of Power are Watt, Work are Joules and Time are Seconds So, Watt-Sec is nothing but Joules So, KWH=3 6Mega Joules One KWH
  • luffy on Socratic
    luffy gets smarter on Socratic luffy joined Socratic 6 5479452054794525 years ago luffy hasn't written a biography yet
  • Question #a39e8 - Socratic
    Therefore, add 3 and take away 3 from the numerator in order to lead to nice cancellation
  • Question #1f1cc - Socratic
    Explanation: #e- e^ [-2x]# can be written as #e- [e^-x]^2# so the expression becomes #-e- [e^-x]^2=1#, tidying up both sides gives # [e^-x]^2= [e-1]#, and then taking the sqare root of both sides,
  • Question #50782 - Socratic
    sf(pH=7 04) This is a very dilute solution of NaOH so I would expect the pH to be 7 or very slightly above Because the concentration is so low we must also take into account the ions that are formed from the dissociation of water: sf(H_2OrightleftharpoonsH^++OH^-) sf(K_w=[H^+][OH^-]=10^(-14) at sf(25^@C) If you do a thought experiment you can imagine adding a small amount of NaOH to water
  • Question #250ef - Socratic
    It is doubled as well Let m_1,m_2 be the masses of two objects We know that m_2=2m_1 The kinetic energy of an object is given by the equation: KE=1 2mv^2 For the first object, its KE is KE_1=1 2m_1v^2 For the second object, its KE is KE_2=1 2m_2v^2 Remember that, m_2=2m_1 : KE_2=1 2*2m_1*v^2 KE_2=mv^2 : KE_2=2KE_1 So, the KE of the second object is double of the first object
  • Question #4d894 - Socratic
    k = (-10) 3 Rearranging 3x + 2y - 5 = 0 to fit the form y = mx + c: 2y = -3x + 5 (2y) 2 = (-3x + 5) 2 y = (-3) 2x + 5 2 So m_1 = (-3) 2 Rearranging kx - 5y + 8 = 0 to
  • Question #4697e - Socratic
    4=E (Note that my pictures are hugely off scale) This may be one of the problems that requires some thinking before trying Let's label what we know Here, I have created a picture in Paint We are trying to solve for E Hmm Let's try to label the angles We know that the angles d and b are right angles Let's name angle c as x We now have: Using the fact that the angles of a triangle always
  • Solving Problems Algebraically and Graphically - Socratic
    Questions and Videos on Solving Problems Algebraically and Graphically, within Precalculus
  • Question #e4223 - Socratic
    This is standardised and usually calculated that way up Sometimes the context of the question requires you to 'bend the rules' a bit but if you declare what you are doing the reader should follow your argument





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